Digital Pulse Stretcher Circuit

If the capacitor is allowed to discharge then it eventually crosses the schmitt trigger threshold and the output changes state.

Digital pulse stretcher circuit.

In one of my design i need to stretch narrow 10 ns pulses coming from photo diode after tia stage if i have to measure the pulse amplitude i have to stretch it at least by a factor of 100 in this search i have found a approach in which the circuit was using a capacitor after its feedback path but i have not understood how exactly the circuit works but when i tried to. A digital pulse stretch circuit for adding a predetermined amount of time to the duration of the input pulse of a wand type or magnetic card reader the input pulse having a rising edge and a. The diode comes from the input so that an active input always keeps the capacitor topped up. We use it for digital logic circuits.

Because the pulse was so short driving the led directly even with a transistor driver created a pulse too short to be seen well. Hi i have a 5v single supply available. This is a pulse generator circuits or standard astable multivibrator oscillator or free running circuit using ic555 timer ne555 lm555. A control on the logic probe allows either the capture and storage of a single event or continuous running.

For detecting a signal from a photodiode amplifier via uc i need to buffer and stretch a pulse which is around 5 ns wide periodic 100 200 ns and down to some 100 mvp amplitude and dc biased somewhere between 1v and 2 5v. The most basic circuit is an rcd network followed by a schmitt trigger. So i needed a pulse stretcher to increase the led s on. Monostable or one shot or pulse extender circuit when the circuit is turned on the output is low and a brief negative pulse on pin 2 will make the output go high for a period of time determined by the value of r and c.

In one of my design i need to stretch narrow ns pulses coming from photo diode after tia stage if i have to measure the pulse amplitude i have to stretch it at least by a factor of 100 in this search i have found a approach in which the circuit was using a capacitor after its feedback path but i have not understood how exactly the circuit works but when i tried to. It is combining analog and digital chip. If pin 2 is low for longer than this period the output will remain high while pin 2 is low and immediately go low when pin.